Thingiverse
Graduated Measuring Cup
door mverive
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Simple graduated cylinder - with a twist! To make it easier to label, this is a graduated cylinder within a tower. Has pouring spouts on both sides, to accommodate left-headed or right-handed people.
This started out as a math exercise: determine the heights of various cylinders to hold different volumes.
Developing in ml is easy: each ml of volume fits in 1 cm^3. 1 cm = 10 mm, so 1 cm^3 = 1000 mm^3.
To convert to ounces, you need to know that 1 fluid ounce = 29.574 ml.
For a cylinder, the volume is base * height. The area of the base is pi * (r^2).
To fit on a small footpring printer (I use a Monoprice Select Mini) with maximum x, y, and z of 120 mm, I decided that I would create a cylinder of the appropriate radius to that each 10mm in height equaled 1 ounce.
So, V= pi * (r^2)
rearranging the equation to solve for r: sqrt(V/pi) = r
if Volume = 29.574, then r = sqrt(29.574/pi)
r = sqrt(29.574/3.1416)
r= sqrt(9.4137)
r = 3.068
Since r= 3.068, the
This started out as a math exercise: determine the heights of various cylinders to hold different volumes.
Developing in ml is easy: each ml of volume fits in 1 cm^3. 1 cm = 10 mm, so 1 cm^3 = 1000 mm^3.
To convert to ounces, you need to know that 1 fluid ounce = 29.574 ml.
For a cylinder, the volume is base * height. The area of the base is pi * (r^2).
To fit on a small footpring printer (I use a Monoprice Select Mini) with maximum x, y, and z of 120 mm, I decided that I would create a cylinder of the appropriate radius to that each 10mm in height equaled 1 ounce.
So, V= pi * (r^2)
rearranging the equation to solve for r: sqrt(V/pi) = r
if Volume = 29.574, then r = sqrt(29.574/pi)
r = sqrt(29.574/3.1416)
r= sqrt(9.4137)
r = 3.068
Since r= 3.068, the
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