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Pentagonal Tiling Type 9
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Michael Tritle
MATH 401 3D printing
George Mason University
09/18/2019
Type 9 pentagons must satisfy the following criteria:
If A, B, C, D and E are the interior angles and a, b, c, d, e are the lengths of edges of the pentagon, then
2A + C = 360°,
D + 2E = 360°, and
b = c = d = e
I. FINDING THE INTERIOR ANGLES
Since we are working with a pentagon, we know that the sum of the interior angles is 540°, so
A + B + C + D + E = 540°.
We would like to find values for A, B, C, D and E that simultaneously the system of equations:
A + B + C + D + E = 540°
2A + C = 360°
D + 2E = 360°.
This system is equivalent to this system
A - B + E = 180°
2B + C - 2E = 0°
D + 2E = 360°
This system has an infinite number of solutions. Choose a B and E such that 0° < B < 180° and 0° < E < 180°, then we get:
A = 180° + B - E
C = 2E - 2B
D = 360° - 2E.
II. FINDING THE MISSING EDGE
For now, we will assume b = c = d = e = 1, This will simplify the calculation for
MATH 401 3D printing
George Mason University
09/18/2019
Type 9 pentagons must satisfy the following criteria:
If A, B, C, D and E are the interior angles and a, b, c, d, e are the lengths of edges of the pentagon, then
2A + C = 360°,
D + 2E = 360°, and
b = c = d = e
I. FINDING THE INTERIOR ANGLES
Since we are working with a pentagon, we know that the sum of the interior angles is 540°, so
A + B + C + D + E = 540°.
We would like to find values for A, B, C, D and E that simultaneously the system of equations:
A + B + C + D + E = 540°
2A + C = 360°
D + 2E = 360°.
This system is equivalent to this system
A - B + E = 180°
2B + C - 2E = 0°
D + 2E = 360°
This system has an infinite number of solutions. Choose a B and E such that 0° < B < 180° and 0° < E < 180°, then we get:
A = 180° + B - E
C = 2E - 2B
D = 360° - 2E.
II. FINDING THE MISSING EDGE
For now, we will assume b = c = d = e = 1, This will simplify the calculation for
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